Overall Goal:

• 1 se n tak numbers print karna, lekin:
• 3 se divisible → "Fizz"
• 5 se divisible → "Buzz"
• Dono se divisible (15) → "FizzBuzz"
• Warna number hi print.

Line 1: Function header

• const fizzBuzz = (n) => { → function jo n tak numbers process karega.

Line 2: Output array

• const out = []; → result store karne ke liye empty array.

Line 3: Loop setup

• for (let i = 1; i <= n; i++) { → 1 se n tak loop:
• let i = 1 → counter start 1 se.
• i <= n → condition: n tak chalega.
• i++ → har iteration me increment.

Line 4: String building logic

• const s = (i % 3 ? '' : 'Fizz') + (i % 5 ? '' : 'Buzz');
• i % 3 → remainder operator: agar divisible hai to 0, warna non-zero:
• i % 3 ? '' : 'Fizz' → ternary operator:
• Agar remainder non-zero (not divisible) → empty string ''.
• Agar remainder 0 (divisible) → 'Fizz'.
• Same logic i % 5 ke liye: divisible ho to 'Buzz', warna ''.
• + operator strings ko concatenate karta hai:
• i=3: '' + 'Buzz' = 'Buzz' (wrong, should be Fizz).
• Wait, let me recalculate: i=3 → i % 3 = 0 → 'Fizz', i % 5 = 3 → '' → 'Fizz' + '' = 'Fizz' ✓
• i=15: 'Fizz' + 'Buzz' = 'FizzBuzz' ✓

Line 5: Push to array

• out.push(s || String(i));
• s || String(i) → logical OR:
• Agar s non-empty hai (Fizz/Buzz/FizzBuzz) → s use karo.
• Agar s empty hai → String(i) use karo (number as string).

Line 6: Return result

• return out; → complete array return.

Real world:

• Interview questions me common hai.
• Logic building practice ke liye perfect.